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Section 2
2-43
FTY = FTZ = 0.55 x F
Y
= 19.8 ksi
Major Axis:
2
6
50 10
0.772 9.87 0.55
yc
b
cz y
xc yc
I
xC
Jd
FF
Sl I l
⎛⎞
⎛⎞
=+
⎜⎟
⎜⎟
⎝⎠
⎝⎠
≤
Where, C
b
= 1.75+ 1.05(M1/M2)+0.3x(M1/M2)
2
Here M1 = -191.36 Kip-in , M2 = -1346.08 Kip-in so C
b
= 1.606
S
zc
=Section modulus w.r.t. compression flange =428/(0.5X13.66)
= 62.7 in
3
I
YC
= tb
3
/12 = 0.53 x 8.0
3
/12 = 22.61in
4
J = (2 x 8.0x0.53
3
+ (13.66 – 2x0.530)x0.305
3
)/3 = 0.911 in
4
2
6
50 10 1.606 22.61 0.911 12.6
0.772 9.87
62.7 48 22.61 48
cz
F
××
⎛⎞ ⎛⎞
=
+=
⎜⎟ ⎜⎟
⎝⎠ ⎝⎠
5
08752.2 psi
Since FCZ is larger than 0.55xF
Y,
FCZ = 0.55xF
Y
= 19.8 ksi
Axial Compression:
F
a
= 0.55 x F
Y
= 19.8 ksi
Shear:
Allowable shear stress as per gross section, F
v
= 0.33xF
Y
= 11.8
ksi
Actual Stress Calculation:
Axial stress (f
a
) = 8.75 / 12.6 = 0.6944ksi.