Filter
Top Products
Section 2
2-45
Where, C
b
= 1.75+ 1.05(M1/M2)+0.3x(M1/M2)
2
Here M1 = 40.14, M2 = -684.4 so C
b
= 1.81
S
zc
=Section modulus w.r.t. compression flange =448/(0.5X15.86)
= 56.5 in
3
I
YC
= tb
3
/12 = 0.43 x 6.99
3
/12 = 12.238 in
4
J = (2 x 6.99x0.43
3
+ (15.86 – 2x0.43)x0.29
3
)/3 = 0.5 in
4
2
6
50 10 1.81 12.238 0.5 15
0.772 9.87
56.5 60 12.238 60
cz
F
××
⎛⎞ ⎛⎞
=
+=
⎜⎟ ⎜⎟
⎝⎠ ⎝⎠
2
63079 psi
Since FCZ is larger than 0.55xF
Y,
FCZ = 0.55xF
Y
= 19.8 ksi
Axial Compression:
Critical (KL/r)
y
= 1.0 x 5x12/1.52 = 39.474
22
2 2 *29000
126.099
36
c
y
E
C
F
ππ
== =
As (KL/r)
y <
C
c
, the allowable axial stress in compression
()
()
2
2
22
39.474 36
36
1 1 16.149
. . 4 2.12 4 29000
yy
a
FKLrF
F
FS E
ππ
⎡⎤
⎡⎤
⎢⎥
=− =− =
⎢⎥
⎢⎥
⎢⎥
⎣⎦
⎣⎦
Shear:
Allowable shear stress as per gross section, F
v
= 0.33xF
Y
= 11.8
ksi